document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39236>Question 39236</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the length if a rectanglur lot with a perimeter of 122 meters if the length is 7 meters more than the width.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24657 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let width be x<BR>\n" );
document.write( "so length is 7 more... ie it is x+7\r<BR>\n" );
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document.write( "So, perimeter = x+x+(x+7)+(x+7) and this equals 122<BR>\n" );
document.write( "x+x+x+7+x+7 = 122<BR>\n" );
document.write( "4x+14 = 122<BR>\n" );
document.write( "4x = 108<BR>\n" );
document.write( "x = 108/4<BR>\n" );
document.write( "x = 27\r<BR>\n" );
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document.write( "so width = 27m<BR>\n" );
document.write( "and length is therefore 34m\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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