document.write( "Question 344577: Solve.
\n" ); document.write( "a. 14+(x+12)^2=35
\n" ); document.write( "b. -20+(x-5)^2=3
\n" ); document.write( "

Algebra.Com's Answer #246567 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
The solutions below take advantage of the fact that the variable is already in a perfect square. There are other ways to solve these (which take a little longer).

\n" ); document.write( "a. \"14%2B%28x%2B12%29%5E2=35\"
\n" ); document.write( "Subtract 14 from each side (isolating the perfect square):
\n" ); document.write( "\"%28x%2B12%29%5E2+=+21\"
\n" ); document.write( "Find the square root of each side:
\n" ); document.write( "\"abs%28x%2B12%29+=+sqrt%2821%29\"
\n" ); document.write( "\"x%2B12+=+0+%2B-+sqrt%2821%29\"
\n" ); document.write( "Subtract 12 (or add a -12):
\n" ); document.write( "\"x+=+-12+%2B-+sqrt%2821%29\"

\n" ); document.write( "b. \"-20%2B%28x-5%29%5E2=3\"
\n" ); document.write( "Add 20 to both sides (to isoloate the perfect square):
\n" ); document.write( "\"%28x-5%29%5E2+=+23\"
\n" ); document.write( "Find the square root of each side:
\n" ); document.write( "\"abs%28x-5%29+=+sqrt%2823%29\"
\n" ); document.write( "\"x-5+=+0+%2B-+sqrt%2823%29\"
\n" ); document.write( "Add 5 to each side:
\n" ); document.write( "\"x+=+5+%2B-+sqrt%2823%29\"
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