document.write( "Question 344479: The length of a rectangle is 7 centimeters less than four times its width. Its area is 15 square centimeters. Find the dimensions of the retangle.\r
\n" ); document.write( "\n" ); document.write( "Width =\r
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Algebra.Com's Answer #246550 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
a=lw
\n" ); document.write( "a=15
\n" ); document.write( "l=4w-7
\n" ); document.write( "15=4w^2-7w
\n" ); document.write( "0=4w^2-7w-15
\n" ); document.write( "w=3 since it cant be negative
\n" ); document.write( "l=5
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"4w%5E2%2B-7w%2B-15+=+0\") has the following solutons:
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\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-7%29%5E2-4%2A4%2A-15=289\".
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\n" ); document.write( " Discriminant d=289 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--7%2B-sqrt%28+289+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"w%5B1%5D+=+%28-%28-7%29%2Bsqrt%28+289+%29%29%2F2%5C4+=+3\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%28-7%29-sqrt%28+289+%29%29%2F2%5C4+=+-1.25\"
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\n" ); document.write( " Quadratic expression \"4w%5E2%2B-7w%2B-15\" can be factored:
\n" ); document.write( " \"4w%5E2%2B-7w%2B-15+=+4%28w-3%29%2A%28w--1.25%29\"
\n" ); document.write( " Again, the answer is: 3, -1.25.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+4%2Ax%5E2%2B-7%2Ax%2B-15+%29\"

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