document.write( "Question 344523: the length of a rectangle is 5cm more than the width. the area is 50cm^2. find the width \n" ); document.write( "

Algebra.Com's Answer #246467 by JBarnum(2146) $\"\"$ $\"About$

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$\"L=5%2BW\"$
\n" ); document.write( " $\"A=50\"$
\n" ); document.write( " $\"A=LW\"$
\n" ); document.write( ".
\n" ); document.write( " $\"50=%285%2BW%29W\"$
\n" ); document.write( " $\"50=W%5E2%2B5W\"$
\n" ); document.write( " $\"0=W%5E2%2B5W-50\"$
\n" ); document.write( "just by looking at this you should see -5 and 10 both add to get +5 and multiply to get -50
\n" ); document.write( " $\"0=%28W-5%29%28W%2B10%29\"$
\n" ); document.write( " $\"W=5\"$ , $\"-10\"$
\n" ); document.write( "since a length cant be negative W=5
\n" ); document.write( "5+5=L
\n" ); document.write( "10=L \n" ); document.write( "

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