document.write( "Question 344366: A civic club charters a bus for one day at a cost of $575. When 2 more people join the group each persons cost decreases by $2. How many people were in the original group.\r
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\n" ); document.write( "\n" ); document.write( "Thought you might solve this by 575/4 or (575-2)4 but it didn't seem to work please help thanks
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Algebra.Com's Answer #246385 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Where's the 4 come from??
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\n" ); document.write( "Assume there are X people going originally.
\n" ); document.write( "Then the cost per person is
\n" ); document.write( "\"C%5B1%5D=575%2FX\"
\n" ); document.write( "When you add the 2 people you now have X+2 people and the cost per person becomes,
\n" ); document.write( "\"C%5B2%5D=575%2F%28X%2B2%29\"
\n" ); document.write( "And you know that,
\n" ); document.write( "\"C%5B2%5D=C%5B1%5D-2\"
\n" ); document.write( "Now substitute into this equation.
\n" ); document.write( "\"575%2F%28X%2B2%29=575%2FX-2\"
\n" ); document.write( "Multiply both sides by the product of the denominators \"X%28X%2B2%29\"
\n" ); document.write( "\"575X=575%28X%2B2%29-2X%28X%2B2%29\"
\n" ); document.write( "\"575X=575X%2B1150-2X%5E2-4X\"
\n" ); document.write( "\"2X%5E2%2B4X-1150=0\"
\n" ); document.write( "\"X%5E2%2B2X-575=0\"
\n" ); document.write( "This equation is factorable.
\n" ); document.write( "\"%28X-23%29%28X%2B25%29=0\"
\n" ); document.write( "Two solutions but only the positive solution makes sense here.
\n" ); document.write( "\"X-23=0\"
\n" ); document.write( "\"X=23\"
\n" ); document.write( "When \"X=23\", \"C=575%2F23=25\"dollars per person
\n" ); document.write( "When \"X=25\", \"C=575%2F25=23\"dollars per person, a $2 reduction.
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