document.write( "Question 39206: I'm having difficulties with this problem:\r
\n" ); document.write( "\n" ); document.write( "\"A chemist has a 30% acid solution and a 60% solution already prepared. How much of each of the two solutions should be mixed to form 300 milliliters (mL) of a 50% soltuion?\r
\n" ); document.write( "\n" ); document.write( "i have the first set of the 2 equation method - at least from what it sounds like i'd be doing that as .3x + .6y = 300mL \r
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Algebra.Com's Answer #24638 by Paul(988) $\"\"$ $\"About$

You can put this solution on YOUR website!
Equation:
\n" ); document.write( " $\"30%28300-x%29%2B60x=50%28300%29\"$
\n" ); document.write( " $\"9000-30x%2B60x=15000\"$
\n" ); document.write( " $\"30x=6000\"$
\n" ); document.write( "x=200 300-200=100
\n" ); document.write( "Hence, for 30% about 100 mm should be used and for 60% about 200 mm should be used.
\n" ); document.write( "Paul. \n" ); document.write( "

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