document.write( "Question 344403: Sandy held garage sale during w/c she charged a dime for everything but accepted a nickel if a buyer bargained well. At the end she had sold 12 items and had a total of 95 cents. She only had nickels & dimes. How many of each did she have? Pls I need the equation \n" ); document.write( "
Algebra.Com's Answer #246333 by josmiceli(19441)\"\" \"About 
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Let \"x\"=number of items that she sold for a nickel
\n" ); document.write( "Then \"12+-+x\" = number of items that she sold for a dime
\n" ); document.write( "given:
\n" ); document.write( "\"5x+%2B+10%2A%2812+-+x%29+=+95\"
\n" ); document.write( "\"5x+%2B+120+-+10x+=+95\"
\n" ); document.write( "\"-5x+=+-25\"
\n" ); document.write( "\"x+=+5\"
\n" ); document.write( "\"12+-+x+=+12+-+5\"
\n" ); document.write( "\"12-+5+=+7\"
\n" ); document.write( "She sold 5 items for a nickel and 7 items for a dime
\n" ); document.write( "check:
\n" ); document.write( "\"5x+%2B+10%2A%2812+-+x%29+=+95\"
\n" ); document.write( "\"5%2A5+%2B+10%2A%2812+-+5%29+=+95\"
\n" ); document.write( "\"25+%2B+10%2A7+=+95\"
\n" ); document.write( "\"25+%2B+70+=+95\"
\n" ); document.write( "\"95+=+95\"
\n" ); document.write( "OK
\n" ); document.write( "
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