document.write( "Question 344348: log(x-3)+log(2)=1 \n" ); document.write( "

Algebra.Com's Answer #246330 by fractalier(6550) $\"\"$ $\"About$

You can put this solution on YOUR website!
From log(x-3)+log(2)=1
\n" ); document.write( "we apply the laws of logs and get
\n" ); document.write( "log(2(x-3)) = 1
\n" ); document.write( "log(2x - 6) = 1
\n" ); document.write( "now exponentiate each side to the base ten and get
\n" ); document.write( "2x - 6 = 10
\n" ); document.write( "2x = 16
\n" ); document.write( "x = 8 \n" ); document.write( "

\n" );