document.write( "Question 344338: One solution contains 10% alcohol while another contains 30% alcohol. How many liters of each should be mixed to give 10 L of a solution 25% alcohol?
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Algebra.Com's Answer #246322 by Fombitz(32388)\"\" \"About 
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Let \"A\" be the amount of 10% alcohol, \"B\" the amount of 30% alcohol.
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\n" ); document.write( "Total volume:
\n" ); document.write( "1.\"A%2BB=10\"
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\n" ); document.write( "Concentration of alcohol:
\n" ); document.write( "\"10A%2B30B=25%2810%29\"
\n" ); document.write( "2.\"A%2B3B=25\"
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\n" ); document.write( "Subtract eq. 1 from eq. 2,
\n" ); document.write( "\"A%2B3B-A-B=25-10\"
\n" ); document.write( "\"2B=15\"
\n" ); document.write( "\"highlight%28B=15%2F2%29\"L
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B15%2F2=10\"
\n" ); document.write( "\"A=20%2F2-15%2F2\"
\n" ); document.write( "\"highlight%28A=5%2F2%29\"L
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