document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=344309>Question 344309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you solve x to the negative third power times x to the negative fourth power? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246312 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the law of exponents, same base, multiplication, exponents add.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E%28-3%29%2Ax%5E%28-4%29=x%5E%28-7%29=1%2Fx%5E7 ALIGN=MIDDLE  ALT=\"x%5E%28-3%29%2Ax%5E%28-4%29=x%5E%28-7%29=1%2Fx%5E7\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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