document.write( "Question 344317: I am trying to figure out how to solve for \"n\" when it is 2 to the \"n\" power in the following equation:
\n" ); document.write( "2^n+6=14.
\n" ); document.write( "2^n+6-6=14-6
\n" ); document.write( "2^n=8
\n" ); document.write( "I am unclear where to go from here. How to I isolate the exponent \"n\" to find the solution?
\n" ); document.write( "

Algebra.Com's Answer #246306 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
You could recognize that
\n" ); document.write( "\"8=2%5E3\" and substitute.
\n" ); document.write( "\"2%5En=2%5E3\"
\n" ); document.write( "\"n=3\"
\n" ); document.write( "or take the log (base 2) of both sides.
\n" ); document.write( "\"log%282%2C%282%5En%29%29=log%282%2C%288%29%29\"
\n" ); document.write( "\"n=log%282%2C%288%29%29\"
\n" ); document.write( "\"n=log%2810%2C%288%29%29%2Flog%2810%2C%282%29%29\"
\n" ); document.write( "\"n=0.90309%2F0.30103\"
\n" ); document.write( "\"n=3\"
\n" ); document.write( "
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