document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=344257>Question 344257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two complementary angles are in the ratio 3:2. the number of degrees in the smaller angle is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246295 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two complementary angles are in the ratio 3:2. the number of degrees in the smaller angle is<BR>\n" );
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document.write( "Let one of the angles be \"x\".<BR>\n" );
document.write( "Then the other is \"90-x\".<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x/(90-x) = 3/2<BR>\n" );
document.write( "2x = 3(90-x)<BR>\n" );
document.write( "2x = 270-3x<BR>\n" );
document.write( "5x = 270<BR>\n" );
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document.write( "x = 54 degrees<BR>\n" );
document.write( "90-x = 36 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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