document.write( "Question 344122: An airplane flies 490 miles with the wind and 330 against the wind in the same length of time. If the speed of the wind is 20, what is the speed of the airplane in still air? \n" ); document.write( "
Algebra.Com's Answer #246263 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "490=(R+20)T \n" ); document.write( "T=490/(R+20) \n" ); document.write( "330=(R-20)T \n" ); document.write( "T=330/(R-20) \n" ); document.write( "490/(R+20)=330/(R-20) CROSS MULTIPLY. \n" ); document.write( "490(R-20)=330(R+20) \n" ); document.write( "490R-9,800=330T+6,600 \n" ); document.write( "490R-330R=6,600+9,800 \n" ); document.write( "160R=16,400 \n" ); document.write( "R=16,400/160 \n" ); document.write( "R=102.5 MPH IS THE PLANES SPEED IN STILL AIR. \n" ); document.write( "PROOF: \n" ); document.write( "490/(102.5+20)=330/(102.5-20) \n" ); document.write( "490/122.5=330/82.5 \n" ); document.write( "4=4 \n" ); document.write( " |