document.write( "Question 37590: Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.\r
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document.write( "Is this how I do it. P = 2l + 2w?
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Algebra.Com's Answer #24625 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.\r \n" ); document.write( "\n" ); document.write( "Yes, use P=2l+2w \n" ); document.write( "400=2l+2w \n" ); document.write( "l+w=200 \n" ); document.write( "l=200-w \n" ); document.write( "Now, Area=lw \n" ); document.write( " A=(200-w)(w)=200w-w^2 \n" ); document.write( "Then, w^2-200w+A=0 \n" ); document.write( "This is a quadratic with a=1,b=-200, c=A \n" ); document.write( "The maximum is at -b/2a = -(-200)/2=100 \n" ); document.write( "So the dimensions are 100' by 100'\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |