document.write( "Question 344159: John's age is three years more than twice Bill's age. Three years ago John was four times as old as Bill was then. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #246243 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! NOW: \n" ); document.write( "JOHN=X+3 \n" ); document.write( "BILL=X \n" ); document.write( "3 YEARS AGO: \n" ); document.write( "JOHN=(X+3-3) \n" ); document.write( "BILL=(X-3)4 \n" ); document.write( "(X+3-3)=4(X-3) \n" ); document.write( "X=4X-12 \n" ); document.write( "X-4X=-12 \n" ); document.write( "-3X=-12 \n" ); document.write( "X=-12/-3 \n" ); document.write( "X=4 BILL'S AGE NOW. \n" ); document.write( "4+3=7 JOHN'S AGE NOW. \n" ); document.write( "PROOF: \n" ); document.write( "(4+3-3)=(4-3)4 \n" ); document.write( "4=1*4 \n" ); document.write( "4=4 \n" ); document.write( " |