document.write( "Question 344159: John's age is three years more than twice Bill's age. Three years ago John was four times as old as Bill was then. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #246243 by checkley77(12844)\"\" \"About 
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NOW:
\n" ); document.write( "JOHN=X+3
\n" ); document.write( "BILL=X
\n" ); document.write( "3 YEARS AGO:
\n" ); document.write( "JOHN=(X+3-3)
\n" ); document.write( "BILL=(X-3)4
\n" ); document.write( "(X+3-3)=4(X-3)
\n" ); document.write( "X=4X-12
\n" ); document.write( "X-4X=-12
\n" ); document.write( "-3X=-12
\n" ); document.write( "X=-12/-3
\n" ); document.write( "X=4 BILL'S AGE NOW.
\n" ); document.write( "4+3=7 JOHN'S AGE NOW.
\n" ); document.write( "PROOF:
\n" ); document.write( "(4+3-3)=(4-3)4
\n" ); document.write( "4=1*4
\n" ); document.write( "4=4
\n" ); document.write( "
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