document.write( "Question 344110: A chemist needs 110 milliters of a 22% solutions but only has 10% and 54% solutions available. Find how many milliters of each solution that should be mixed to get the desired solution?
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Algebra.Com's Answer #246214 by checkley77(12844)\"\" \"About 
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.54X+.10(110-X)=.22*110
\n" ); document.write( ".54X+11-.10X=24.2
\n" ); document.write( ".44X=24.2-11
\n" ); document.write( ".44X=13.2
\n" ); document.write( "X=13.2/.44
\n" ); document.write( "X=30 ML. OF 54% SOLUTION IS USED.
\n" ); document.write( "110-30=80 ML. OF 10% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".54*30+.10*80=.22*110
\n" ); document.write( "16.2+8=24.2
\n" ); document.write( "24.2=24.2
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