document.write( "Question 344049: can you please explain how you get the answer step by step\r
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document.write( "Mr. Wise bought $1950 woth of stock, some at $3 per share and some at $4.50 per share. If he bought a total of 450 shares of stock, how many of each did he buy?\r
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document.write( "thank you
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document.write( "april \n" );
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Algebra.Com's Answer #246192 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Mr. Wise bought $1950 woth of stock, some at $3 per share and some at $4.50 per share. If he bought a total of 450 shares of stock, how many of each did he buy? \n" ); document.write( ". \n" ); document.write( "Let x = number of $3.50 shares purchased \n" ); document.write( "and y = number of $4.50 shares purchased \n" ); document.write( ". \n" ); document.write( "From: \"Mr. Wise bought $1950 woth of stock\" we get \n" ); document.write( "3.50x + 4.50y = 1950 (equation 1) \n" ); document.write( ". \n" ); document.write( "From: \"If he bought a total of 450 shares of stock\" we get \n" ); document.write( "x + y = 450 (equation 2) \n" ); document.write( ". \n" ); document.write( "Apply the \"addition\" method: \n" ); document.write( "3.50x + 4.50y = 1950 \n" ); document.write( "x + y = 450 \n" ); document.write( ". \n" ); document.write( "Multiply the bottom equation by -3.50: \n" ); document.write( "3.50x + 4.50y = 1950 \n" ); document.write( "-3.50x - 3.50y = -1575 \n" ); document.write( ". \n" ); document.write( "Add the two equations together: \n" ); document.write( "3.50x + 4.50y = 1950 \n" ); document.write( "-3.50x - 3.50y = -1575 \n" ); document.write( "-------------------------- \n" ); document.write( "1.50y = 375 \n" ); document.write( "y = 250 shares at $4.50 \n" ); document.write( ". \n" ); document.write( "Shares at $3.50, substitute above into equation 2: \n" ); document.write( "x + y = 450 \n" ); document.write( "x + 250 = 450 \n" ); document.write( "x = 200 shares at $3.50 \n" ); document.write( " \n" ); document.write( " |