document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=344095>Question 344095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the mesures of two complmentary angles, <A and <B, if m<A = 7x+4 and m<B = 4x+9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246185 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "I don't know what a 'mesure' is or what 'complmentary' means.  Now if you want the measure of two complementary angles then pick a value greater than zero but less than 90.  Subtract that value from 90.  The value you picked is one measure of a pair of complementary angles and the result of your subtraction problem is the other measure.\r<BR>\n" );
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document.write( "For instance, let's say that I picked <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 0.000001^\circ\"> as one angle, then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 90^\circ\ -\ 0.000001^\circ\ =\ 89.999999^\circ\"> is the other one.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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