document.write( "Question 344035: OK my word problem is \"Melissa is 24 years younger than Joyce. In 2 years, Joyce will be 3 times as old as Melissa will be then. How old are they now?\"\r
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document.write( "My teacher told me to set it up into a table. How i think the table will be set up like this:\r
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document.write( " Now -------- In 2 yrs
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document.write( "Melissa: x-24 x-24+2
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document.write( "Joyce: x 3(x-24+2)
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document.write( "And when i set up the equation it came out to be:
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document.write( "x-24+2=3(x-24+2)\r
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document.write( "Im not sure if that is the right way to set it up. I am horrible at Algebra and i really need your help\r
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document.write( "So my question is: Is my equation set up right or do i need to do it a whole dfferent way? \n" );
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Algebra.Com's Answer #246164 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! You have the right idea!..Just using more info than you need to solve at first. \n" ); document.write( "The way to look at it is that Joyce will \"always\" be 24 yrs older than Melissa! \n" ); document.write( "so..the 2 years is not important information to set up the equation you need AT FIRST if you just let J be Joyces age in two years time.\r \n" ); document.write( "\n" ); document.write( "THE QUESTION STATES THEN THE FOLLOWING TO BE TRUE(in two years) \n" ); document.write( "Joyce will be 3 times as old as Melissa and, as always, 24 years older. \n" ); document.write( "J =3(J-24) \r \n" ); document.write( "\n" ); document.write( "Simplify: \n" ); document.write( "J = 3*J -72 \n" ); document.write( "0=2*J -72 \n" ); document.write( "72=2*J \n" ); document.write( "J=36 (THAT'S THE AGE JOYCE WILL BE IN 2 YEARS) Melissa(36/3)or 12 in two years \n" ); document.write( "How old are they now?\" Joyce is 34 and Melissa is 10\r \n" ); document.write( "\n" ); document.write( "Check your answer: Joyce is always 24 years older than Melissa.\r \n" ); document.write( "\n" ); document.write( "In this case it was the easiest to just set up what the problem said would be true in two years and work backwards from there! \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |