document.write( "Question 343880: Candle A and candle B are of the same length. Candle A, which is broader, can burn for 5 h while Candle B, the thinner candle, can burn for 4 h. If both candles are lighted at the same time, how long does it take for Candle A to be twice as long as Candle B? \n" ); document.write( "
Algebra.Com's Answer #246146 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Candle A and candle B are of the same length.
\n" ); document.write( " Candle A, which is broader, can burn for 5 h
\n" ); document.write( " while Candle B, the thinner candle, can burn for 4 h.
\n" ); document.write( " If both candles are lit at the same time, how long does it take for
\n" ); document.write( " Candle A to be twice as long as Candle B?
\n" ); document.write( ":
\n" ); document.write( "It would be convenient to choose a length for both candles, say 20 inches
\n" ); document.write( "then
\n" ); document.write( "Candle A will burn 20/5, 4 in/hr
\n" ); document.write( "Candle B will burn 20/4, 5 in/hr
\n" ); document.write( ":
\n" ); document.write( "Let t = time in hrs when candle A will be twice as long as Candle B
\n" ); document.write( "20 - 4t = 2(20-5t)
\n" ); document.write( "20 - 4t = 40 - 10t
\n" ); document.write( "-4t + 10t = 40 - 20
\n" ); document.write( "6t = 20
\n" ); document.write( "t = \"20%2F6\"
\n" ); document.write( "t = \"10%2F3\" or 3\"1%2F3\" hrs for A to be twice as long as B
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the length of each after 3.33 hrs
\n" ); document.write( "20 - 4(3.33) = 6.67 inches
\n" ); document.write( "20 - 5(3.33) = 3.335 inches, confirms our solution
\n" ); document.write( "
\n" );