document.write( "Question 344005: Sue walked to her school at 2 miles per hour, picked up her bicycle and rode back home at 10 miles per hour. If the round trip took 1 1/2 hours, how far is the school from Sue's house? \n" ); document.write( "
Algebra.Com's Answer #246118 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! NEED TO KNOW: \n" ); document.write( "RATE*TIME = DISTANCE TRAVELED. \n" ); document.write( "LET T REPRESENT THE TIME IT TOOK TO WALK TO SCHOOL. \n" ); document.write( "THE QUESTION STATES THE FOLLOWING TO BE TRUE. ROUND TRIP TOOK 3/2 hrs. \n" ); document.write( "That is: (3/2hr - T) would be the time remaining to ride back. \n" ); document.write( "USING THE DISTANCE FORMULA: WAY TO = WAY BACK \n" ); document.write( "2mi/hr *T = 10mi/hr *(3/2hr -T) \n" ); document.write( "SOLVE: \n" ); document.write( "2mi/hr *T = 15mi/hr -10mi/hr*T\r \n" ); document.write( "\n" ); document.write( "12mi/hr *T = 15mi/hr \n" ); document.write( "T= 15/12 hr or 1 1/4 hrs \n" ); document.write( "T remaining for ride back 1/4 hr \n" ); document.write( "SUBSTITUTING BACK INTO THE DISTANCE FORMULA \n" ); document.write( "10mi/hr * 1/4 hr = 10/4 mi or 2.5 miles is the distance the school is from home!! \n" ); document.write( " |