document.write( "Question 344014: In toasting three fair coins at once. what is the probability of getting
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document.write( "1. at most two heads
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document.write( "2. at least one head
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document.write( "3. more heads than tails
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document.write( "4. no head
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document.write( "5. exactly two heads \n" );
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Algebra.Com's Answer #246109 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Look at all of totality of outcomes. \n" ); document.write( "There are \n" ); document.write( "1.H H H \n" ); document.write( "2.H H T \n" ); document.write( "3.H T H \n" ); document.write( "4.H T T \n" ); document.write( "5.T H H \n" ); document.write( "6.T H T \n" ); document.write( "7.T T H \n" ); document.write( "8.T T T \n" ); document.write( "Now that you have all of the outcomes, you can answer all of your questions.\r \n" ); document.write( "\n" ); document.write( "1. \"at most two heads\"-Means 2 H or less. \n" ); document.write( "Count the number of outcomes that have 2 H or less. \n" ); document.write( "There are 7 possible outcomes(2,3,4,5,6,7,8). \n" ); document.write( "The probability is possible outcomes divided by total outcomes. \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "2. At least 1 H- Again there are 7 of them (1,2,3,4,5,6,7) \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Now complete the remaining questions in a similar way.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |