document.write( "Question 343976: one positive number is 3 larger than another number. The sum of their squares is 17. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #246088 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "Let x be one number and y be the other so we can set up 2 equation:
\n" ); document.write( "x=y+3
\n" ); document.write( "x^2+y^2=17
\n" ); document.write( "Substitute the first into the second equation:
\n" ); document.write( "(y+3)^2 +y^2=17
\n" ); document.write( "Rewrite this as:
\n" ); document.write( "y^2+6y+9+y^2-17=0
\n" ); document.write( "Now combine like terms:
\n" ); document.write( "2y^2+6y-8=0
\n" ); document.write( "Factor this to get:
\n" ); document.write( "(2y+8)(y-1)=0
\n" ); document.write( "Solve for y:
\n" ); document.write( "y=1
\n" ); document.write( "y=-4
\n" ); document.write( "The only number that works here is:
\n" ); document.write( "y=1 So x=4
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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