document.write( "Question 343949: use s=n^2 to find the sum of 1+3+5+....+501.
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Algebra.Com's Answer #246061 by stanbon(75887)\"\" \"About 
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find the sum of 1+3+5+....+501
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\n" ); document.write( "1st find \"n\" if a(1) = 1 and d = 2
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\n" ); document.write( "Using a(n) = a(1) + (n-1)d you get:
\n" ); document.write( "501 = 1 + (n-1)2
\n" ); document.write( "500 = 2(n-1)
\n" ); document.write( "250 = n-1
\n" ); document.write( "n = 251
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\n" ); document.write( "Find the sum using S(n)=(n/2)(1 + 501)
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\n" ); document.write( "S(251) = 251/2(502) = 251*251 = 63001
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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