document.write( "Question 343949: use s=n^2 to find the sum of 1+3+5+....+501.
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Algebra.Com's Answer #246061 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the sum of 1+3+5+....+501 \n" ); document.write( "----------------- \n" ); document.write( "1st find \"n\" if a(1) = 1 and d = 2 \n" ); document.write( "---- \n" ); document.write( "Using a(n) = a(1) + (n-1)d you get: \n" ); document.write( "501 = 1 + (n-1)2 \n" ); document.write( "500 = 2(n-1) \n" ); document.write( "250 = n-1 \n" ); document.write( "n = 251 \n" ); document.write( "---------------------- \n" ); document.write( "Find the sum using S(n)=(n/2)(1 + 501) \n" ); document.write( "--- \n" ); document.write( "S(251) = 251/2(502) = 251*251 = 63001 \n" ); document.write( "========================================= \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |