document.write( "Question 343639: Larry starts cycling at 20 mi/hr. One hour later, Rebecca starts cycling from the same place at 25 mi/hr, going in the same direction on the same road as Larry. How long will it take Rebecca to catch up to Larry?\r
\n" ); document.write( "\n" ); document.write( "*Someone told me to do
\n" ); document.write( "20T = 25(T-1)
\n" ); document.write( "20T = 25T - 25
\n" ); document.write( "20T - 25T = -25
\n" ); document.write( "-5T = -25
\n" ); document.write( "T = -25/-5
\n" ); document.write( "T = 5 hours.
\n" ); document.write( "I am not sure if this is right? If it is right, I don't understand what everything stands for or the formula used. I need an explanation please.
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Algebra.Com's Answer #245918 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
Rebecca catches Larry when they have both traveled the same distance\r
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\n" ); document.write( "\n" ); document.write( "distance equals rate multiplied by time\r
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\n" ); document.write( "\n" ); document.write( "Rebecca's rate is 25 mph and her time is one hr less than Larry's\r
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\n" ); document.write( "\n" ); document.write( "Larry's rate is 20 mph\r
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\n" ); document.write( "\n" ); document.write( "the T in the equations represents Larry's time\r
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\n" ); document.write( "\n" ); document.write( "depending on your viewpoint, you might say that Rebecca's time to catch Larry doesn't start until Rebecca starts
\n" ); document.write( "___ so the answer is either 4 hr or 5 hr\r
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\n" ); document.write( "\n" ); document.write( "hope this helps
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