document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343639>Question 343639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Larry starts cycling at 20 mi/hr. One hour later, Rebecca starts cycling from the same place at 25 mi/hr, going in the same direction on the same road as Larry. How long will it take Rebecca to catch up to Larry?\r<BR>\n" );
document.write( "\n" );
document.write( "*Someone told me to do<BR>\n" );
document.write( "20T = 25(T-1)<BR>\n" );
document.write( "20T = 25T - 25<BR>\n" );
document.write( "20T - 25T = -25<BR>\n" );
document.write( "-5T = -25<BR>\n" );
document.write( "T = -25/-5<BR>\n" );
document.write( "T = 5 hours.<BR>\n" );
document.write( "I am not sure if this is right? If it is right, I don't understand what everything stands for or the formula used. I need an explanation please.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245915 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Larry starts cycling at 20 mi/hr. One hour later, Rebecca starts cycling from the same place at 25 mi/hr, going in the same direction on the same road as Larry. How long will it take Rebecca to catch up to Larry?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "This is right, this equation makes use of the fact that when R catch L then<BR>\n" );
document.write( "they will have traveled the same distance.<BR>\n" );
document.write( "Dist = speed * time<BR>\n" );
document.write( ":<BR>\n" );
document.write( "T = L's travel time. (dist = 20T)<BR>\n" );
document.write( "R started 1 hour later so<BR>\n" );
document.write( "(T-1) = R's travel time. dist = (25(t-1))<BR>\n" );
document.write( ":<BR>\n" );
document.write( "With this in mind, the equation is:<BR>\n" );
document.write( "L's dist = R's dist<BR>\n" );
document.write( "20T = 25(T-1)<BR>\n" );
document.write( "20T = 25T - 25<BR>\n" );
document.write( "20T - 25T = -25<BR>\n" );
document.write( "-5T = -25<BR>\n" );
document.write( "T = -25/-5<BR>\n" );
document.write( "T = 5 hours.<BR>\n" );
document.write( "YOu solved for T correctly, you can prove this by finding the dist each has<BR>\n" );
document.write( "traveled, they should be equal<BR>\n" );
document.write( "L's dist: 20*5 = 100 mi<BR>\n" );
document.write( "R's dist: 25(5-1) = 100 mi also<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Did this shed some light on this kind of problem, any questions? use the comment feature. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );