document.write( "Question 342987: Please solve algebraically:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B7x+-+y+=+12+-+y%5E2\"
\n" ); document.write( "\"x%5E2+%2B+y%5E2+%2B+6x+%2B+3y+=+4\"\r
\n" ); document.write( "\n" ); document.write( "I do not know really where to start on this one, I would think that you would complete the square for the second equation to begin. However, after that I do not know what to do with the first equation.\r
\n" ); document.write( "\n" ); document.write( "Any help would be greatly appreciated as this seems difficult to me, thank you so so much!
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #245904 by Sphynx pinastri(7)\"\" \"About 
You can put this solution on YOUR website!
First, simplify the equations
\n" ); document.write( "\"x%5E2+%2B+y%5E2+%2B+7x+-+y+-+12+=+0\"
\n" ); document.write( "\"x%5E2+%2B+y%5E2+%2B+6x+%2B+3y+-+4+=+0\"
\n" ); document.write( "Subtract the equations from each other to get
\n" ); document.write( "a linear dependency between x and y.\r
\n" ); document.write( "\n" ); document.write( "Solve it relatively to x or y and substitute to
\n" ); document.write( "the one of the original equations.\r
\n" ); document.write( "\n" ); document.write( "Solve the resulting square equation.
\n" ); document.write( "The rest of the solution is left to the
\n" ); document.write( "exercise of the reader.
\n" ); document.write( "
\n" );