document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343621>Question 343621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a certain radio active isotope decays at a rate of .2% annually. Determine the half life of the isotope, to the nearest year. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245903 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1 - .002)^h = 1/2\r<BR>\n" );
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document.write( "h * log(1 - .002) = log(1/2)\r<BR>\n" );
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document.write( "h = [log(1/2)] / [log(1 - .002)] </SPAN>\n" );
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