document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343704>Question 343704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular field is 45 ft greater than its width. How much fencing is needed to enclose the field and divide it into two parts? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245901 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular field is 45 ft greater than its width. How much fencing is needed to enclose the field and divide it into two parts?<BR>\n" );
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document.write( "Let the width be \"W\".<BR>\n" );
document.write( "Then Length = W+45<BR>\n" );
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document.write( "Draw a picture and label the line segments.<BR>\n" );
document.write( "Two Solutions:<BR>\n" );
document.write( "3(W+45)+ 2w = 3W+135+2W = 5W+135 ft<BR>\n" );
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document.write( "OR<BR>\n" );
document.write( "3(W)+2(W+45) = 3W+2W+90 = 5W+90 ft<BR>\n" );
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document.write( "The anwer depends on where you put the dividing side.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );