document.write( "Question 343669: A fire truck is called into a scene. Three minutes later, a second truck is called. The first truck averages on 30 miles per hour, but the second truck averages 60 miles per hour. The trucks travel a total of 12 miles and arrive at the same time.\r
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Algebra.Com's Answer #245895 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the distance in miles traveled by the first truck.\r
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\n" ); document.write( "\n" ); document.write( "Let represent the travel time of the first truck in minutes.\r
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\n" ); document.write( "\n" ); document.write( "Since we are expressing time in minutes, convert 30 miles per hour to 1/2 mile per minute and 60 miles per hour to 1 mile per minute.\r
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\n" ); document.write( "\n" ); document.write( "The first truck:\r
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\n" ); document.write( "\n" ); document.write( "If the first truck traveled miles, then the second truck traveled miles. If the first truck traveled for minutes, then the second truck, having been called 3 minutes later, traveled minutes.\r
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\n" ); document.write( "\n" ); document.write( "The second truck:\r
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\n" ); document.write( "\n" ); document.write( "(Remember, the second truck's rate was 1 mile per minute)\r
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\n" ); document.write( "\n" ); document.write( "Solve for \r
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\n" ); document.write( "\n" ); document.write( "Now we have two expressions each of which is equal to , so set them equal to each other:\r
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\n" ); document.write( "\n" ); document.write( "Solve for to get the time for the first truck. Substitute into to find the distance for the second truck.\r
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\n" ); document.write( "\n" ); document.write( "Subtract to get the time for the second truck.\r
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\n" ); document.write( "\n" ); document.write( "Subtract to get the distance for the second truck.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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