document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39138>Question 39138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> George weighs 60 lbs. more than 1/2 his younger brother Galen's weight. If their weights balance when George is 4 ft. from the fulcrum on a 10 ft. long teeterboard, what are their weights?\r<BR>\n" );
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document.write( "(not from a text) I need help on this please, Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24589 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the teeterboard is 10 feet, then the brother is assumed to  be 5 ft from the fulcrum...George is 4 ft from it...<BR>\n" );
document.write( "Let x = the brother's weight.<BR>\n" );
document.write( "The 60 + (1/2)x is George's weight.<BR>\n" );
document.write( "Since they balance, we have<BR>\n" );
document.write( "5x = 4(60 + (1/2)x)<BR>\n" );
document.write( "5x = 240 + 2x<BR>\n" );
document.write( "3x = 240<BR>\n" );
document.write( "x = 80 and brother's weight<BR>\n" );
document.write( "George weighs 60 + (1/2)(80) = 100 lbs... </SPAN>\n" );
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