document.write( "Question 343393: IT CAN TAKE 12 HOURS TO FILL A SWIMMING POOL USING 2 PIPES.IF THE PIPE OF LARGER DIAMETER IS USED FOR 4 HOURS,THE PIPE OF SMALLER DIAMETER IS USED FOR 9 HOURS,ONLY HALF OF THE POOL CAN BE FILLED.HOW LONG WOULD IT TAKE FOR EACH PIPE TO FILL THE POOL SEPERATELY? \n" ); document.write( "
Algebra.Com's Answer #245839 by ankor@dixie-net.com(22740)\"\" \"About 
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IT CAN TAKE 12 HOURS TO FILL A SWIMMING POOL USING 2 PIPES.
\n" ); document.write( "IF THE PIPE OF LARGER DIAMETER IS USED FOR 4 HOURS,THE PIPE OF SMALLER
\n" ); document.write( " DIAMETER IS USED FOR 9 HOURS, ONLY HALF OF THE POOL CAN BE FILLED.
\n" ); document.write( "HOW LONG WOULD IT TAKE FOR EACH PIPE TO FILL THE POOL SEPARATELY?
\n" ); document.write( ":
\n" ); document.write( "Let a = larger pipe time to fill the pool by itself
\n" ); document.write( "Let b = smaller pipe time to fill it
\n" ); document.write( ":
\n" ); document.write( "Let a full pool = 1
\n" ); document.write( "then
\n" ); document.write( "half full pool = .5
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ";
\n" ); document.write( "\"It can take 12 hr to fill a swimming pool using 2 pipes\"
\n" ); document.write( "\"12%2Fa\" + \"12%2Fb\" = 1
\n" ); document.write( ":
\n" ); document.write( "\"If the larger pipe is used for 4 hrs and the smaller pipe for 9 hrs, only half
\n" ); document.write( "the pool will be filled\"
\n" ); document.write( "\"4%2Fa\" + \"9%2Fb\" = .5
\n" ); document.write( ":
\n" ); document.write( "Use elimination, multiply the above equation by 3, subtract the 1st equation
\n" ); document.write( "\"12%2Fa\" + \"27%2Fb\" = 1.5
\n" ); document.write( "\"12%2Fa\" + \"12%2Fb\" = 1
\n" ); document.write( "------------------------------subtraction eliminates a find b
\n" ); document.write( "\"15%2Fb\" = .5
\n" ); document.write( "15 = .5b
\n" ); document.write( "b = 30 hrs for the small pipe alone
\n" ); document.write( ":
\n" ); document.write( "Find a using the 1st equation
\n" ); document.write( "\"12%2Fa\" + \"12%2F30\" = 1
\n" ); document.write( "Multiply by 30a
\n" ); document.write( "30(12) + 12a = 30a
\n" ); document.write( "360 = 30a - 12a
\n" ); document.write( "360 = 18a
\n" ); document.write( "a = \"360%2F18\"
\n" ); document.write( "a = 20 hrs for the large pipe alone
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this in the 2nd equation
\n" ); document.write( "\"4%2F20\" + \"9%2F30\" =
\n" ); document.write( ".2 + .3 = .5
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Summarize: the large pipe requires 20 hr alone, the small pipe 30 hrs alone
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