document.write( "Question 343393: IT CAN TAKE 12 HOURS TO FILL A SWIMMING POOL USING 2 PIPES.IF THE PIPE OF LARGER DIAMETER IS USED FOR 4 HOURS,THE PIPE OF SMALLER DIAMETER IS USED FOR 9 HOURS,ONLY HALF OF THE POOL CAN BE FILLED.HOW LONG WOULD IT TAKE FOR EACH PIPE TO FILL THE POOL SEPERATELY? \n" ); document.write( "
Algebra.Com's Answer #245839 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! IT CAN TAKE 12 HOURS TO FILL A SWIMMING POOL USING 2 PIPES. \n" ); document.write( "IF THE PIPE OF LARGER DIAMETER IS USED FOR 4 HOURS,THE PIPE OF SMALLER \n" ); document.write( " DIAMETER IS USED FOR 9 HOURS, ONLY HALF OF THE POOL CAN BE FILLED. \n" ); document.write( "HOW LONG WOULD IT TAKE FOR EACH PIPE TO FILL THE POOL SEPARATELY? \n" ); document.write( ": \n" ); document.write( "Let a = larger pipe time to fill the pool by itself \n" ); document.write( "Let b = smaller pipe time to fill it \n" ); document.write( ": \n" ); document.write( "Let a full pool = 1 \n" ); document.write( "then \n" ); document.write( "half full pool = .5 \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( "; \n" ); document.write( "\"It can take 12 hr to fill a swimming pool using 2 pipes\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"If the larger pipe is used for 4 hrs and the smaller pipe for 9 hrs, only half \n" ); document.write( "the pool will be filled\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Use elimination, multiply the above equation by 3, subtract the 1st equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------subtraction eliminates a find b \n" ); document.write( " \n" ); document.write( "15 = .5b \n" ); document.write( "b = 30 hrs for the small pipe alone \n" ); document.write( ": \n" ); document.write( "Find a using the 1st equation \n" ); document.write( " \n" ); document.write( "Multiply by 30a \n" ); document.write( "30(12) + 12a = 30a \n" ); document.write( "360 = 30a - 12a \n" ); document.write( "360 = 18a \n" ); document.write( "a = \n" ); document.write( "a = 20 hrs for the large pipe alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this in the 2nd equation \n" ); document.write( " \n" ); document.write( ".2 + .3 = .5 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Summarize: the large pipe requires 20 hr alone, the small pipe 30 hrs alone \n" ); document.write( " |