document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343455>Question 343455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose perimeter is 26 meters and whose arae is 40 square meters. I know this is very basic, but I have not been in a classroom in over 35 years. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245767 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2W ___ 26 = 2L + 2W ___ 13 = L + W\r<BR>\n" );
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document.write( "A = L * W ___ 40 = L * W\r<BR>\n" );
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document.write( "you are looking for two numbers whose sum is 13 and whose product is 40<BR>\n" );
document.write( "___ like 8 and 5\r<BR>\n" );
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document.write( "using equations\r<BR>\n" );
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document.write( "L = 13 - W\r<BR>\n" );
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document.write( "substituting ___ 40 = (13 - W) * W ___ 40 = 13W - W^2 ___ W^2 - 13W + 40 = 0\r<BR>\n" );
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document.write( "factoring ___ (W - 8)(W - 5) = 0\r<BR>\n" );
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document.write( "W - 8 = 0 ___ W = 8\r<BR>\n" );
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document.write( "W - 5 = 0 ___ W = 5\r<BR>\n" );
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document.write( "one dimension is 5 and the other is 8 </SPAN>\n" );
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