document.write( "Question 343289: A mechanic has two antifreeze solutions. One is 70% antinfreeze and the other is 40% antifreeze. How much of each solution should be mixed to make 60 gallons of a solution that is 52% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #245706 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 70% antinfreeze, B the amount of 40% antifreeze.
\n" ); document.write( "1.\"A%2BB=60\"
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\n" ); document.write( "\"70A%2B40B=52%2860%29\"
\n" ); document.write( "2.\"7A%2B4B=312\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A=60-B\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"7%2860-B%29%2B4B=312\"
\n" ); document.write( "\"420-7B%2B4B=312\"
\n" ); document.write( "\"-3B=-108\"
\n" ); document.write( "\"highlight%28B=36%29\"gallons
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B36=60\"
\n" ); document.write( "\"highlight%28A=24%29\"gallons
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