document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343338>Question 343338</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the second angle of a triangular kite is four times as large as the first. The third angle  is 5 degrees more than the sum of the other two angles.  Find the measure  of the second angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245686 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let first angle be x<BR>\n" );
document.write( "the second angle = 4x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Third angle =(x+4x)+5<BR>\n" );
document.write( "....<BR>\n" );
document.write( "x+4x+5x+5 =180<BR>\n" );
document.write( "10x+5 =180<BR>\n" );
document.write( "-5<BR>\n" );
document.write( "10x+5-5 = 180-5<BR>\n" );
document.write( "10x = 175<BR>\n" );
document.write( "/10<BR>\n" );
document.write( "x= 175/10<BR>\n" );
document.write( "x =17.5 first angle<BR>\n" );
document.write( "second angle = 4x = 4*17.5 = 70 deg<BR>\n" );
document.write( "third angle = 5x+5 = 5*17.5 + 5= 92.5 deg<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );