document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39139>Question 39139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me rewrite the expression 2sqrt3+sqrt2/sqrt3-sqrt2 so there are no radicals in the denominator?  I guess we could say rationalize the denominator.  Thank you so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24568 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay we multiply top and bottom by the conjugate of the denominator...so we get<BR>\n" );
document.write( "(2sqrt3+sqrt2)/(sqrt3-sqrt2) * [(sqrt3+sqrt2)/(sqrt3+sqrt2)] =<BR>\n" );
document.write( "[2sqrt(9) - 2sqrt(6) + sqrt(6) - 2] / (3 - 2) =<BR>\n" );
document.write( "4 - sqrt(6) </SPAN>\n" );
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