document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343341>Question 343341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if two angles are supplementary and the larger angle is 20 degrees less then three times the the smaller angle find the measure of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245675 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let smaller angle be x<BR>\n" );
document.write( "the supplement will be 180-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "180-x =3x-20<BR>\n" );
document.write( "3x+x=180+20<BR>\n" );
document.write( "4x =200<BR>\n" );
document.write( "/4 <BR>\n" );
document.write( "x= 50 deg.<BR>\n" );
document.write( "the other angle = 180-x<BR>\n" );
document.write( "=180-50 = 130 deg. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );