document.write( "Question 343342: One side of a triangle is half the longest side. The third side is 10 meters less than the longest side. The peremiter is 53 feet. Find the shortest side.
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Algebra.Com's Answer #245666 by mananth(16946)\"\" \"About 
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let longest side = x
\n" ); document.write( "one side = x/2
\n" ); document.write( "third side =x-10
\n" ); document.write( "...
\n" ); document.write( "x+x/2 + x-10=53
\n" ); document.write( "+10
\n" ); document.write( "2x+x/2 +10-10=53+10
\n" ); document.write( "2x+x/2 = 63
\n" ); document.write( "(4x+x)/2 =63
\n" ); document.write( "LCD =2
\n" ); document.write( "5x/2 = 63
\n" ); document.write( "multiply by 2
\n" ); document.write( "5x= 2*63
\n" ); document.write( "/5
\n" ); document.write( "x= 2*63/5
\n" ); document.write( "=25.2
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\n" ); document.write( "x/2 = 25.2 /2 = 12.6
\n" ); document.write( "x-10 = 25.2 -10=15.2
\n" ); document.write( "The sides are
\n" ); document.write( "25.2 , 12.6, 15.2
\n" ); document.write( "Check
\n" ); document.write( "Their sum = 53
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