document.write( "Question 343342: One side of a triangle is half the longest side. The third side is 10 meters less than the longest side. The peremiter is 53 feet. Find the shortest side.
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Algebra.Com's Answer #245666 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let longest side = x \n" ); document.write( "one side = x/2 \n" ); document.write( "third side =x-10 \n" ); document.write( "... \n" ); document.write( "x+x/2 + x-10=53 \n" ); document.write( "+10 \n" ); document.write( "2x+x/2 +10-10=53+10 \n" ); document.write( "2x+x/2 = 63 \n" ); document.write( "(4x+x)/2 =63 \n" ); document.write( "LCD =2 \n" ); document.write( "5x/2 = 63 \n" ); document.write( "multiply by 2 \n" ); document.write( "5x= 2*63 \n" ); document.write( "/5 \n" ); document.write( "x= 2*63/5 \n" ); document.write( "=25.2 \n" ); document.write( ".. \n" ); document.write( "x/2 = 25.2 /2 = 12.6 \n" ); document.write( "x-10 = 25.2 -10=15.2 \n" ); document.write( "The sides are \n" ); document.write( "25.2 , 12.6, 15.2 \n" ); document.write( "Check \n" ); document.write( "Their sum = 53 \n" ); document.write( " |