document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343343>Question 343343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Barbara had money in two accounts. She had $900 more in an account paying 8% annual interest than she had in an account paying 6% annual interest. If she earned $240 in interest for the year, how much did she have invested in each account? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245664 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6% account be $ x<BR>\n" );
document.write( "8% account she has x+900<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Total interest she earned =$240<BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.06x+0.08(x+900)=240<BR>\n" );
document.write( "0.06x +0.08x + 72=240<BR>\n" );
document.write( "0.14x= 240-72<BR>\n" );
document.write( "0.14x= 168<BR>\n" );
document.write( "/0.14<BR>\n" );
document.write( "x= 168/0.14<BR>\n" );
document.write( "=$1200 amount at 6 %<BR>\n" );
document.write( "1200+900 = $2100 at 8% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );