document.write( "Question 343286: One number is 5 more than another number. If the smaller number is doubled and added to 3 times the larger number, the sum is 80. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #245656 by haileytucki(390)\"\" \"About 
You can put this solution on YOUR website!
x+5=y_2x+3y=80\r
\n" ); document.write( "\n" ); document.write( "Since 5 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 5 from both sides.
\n" ); document.write( "x=-5+y_2x+3y=80\r
\n" ); document.write( "\n" ); document.write( "Move all terms not containing x to the right-hand side of the equation.
\n" ); document.write( "x=y-5_2x+3y=80\r
\n" ); document.write( "\n" ); document.write( "Replace all occurrences of x with the solution found by solving the last equation for x. In this case, the value substituted is y-5.
\n" ); document.write( "x=y-5_2(y-5)+3y=80\r
\n" ); document.write( "\n" ); document.write( "Multiply 2 by each term inside the parentheses.
\n" ); document.write( "x=y-5_2y-10+3y=80\r
\n" ); document.write( "\n" ); document.write( "Since 2y and 3y are like terms, add 3y to 2y to get 5y.
\n" ); document.write( "x=y-5_5y-10=80\r
\n" ); document.write( "\n" ); document.write( "Since -10 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 10 to both sides.
\n" ); document.write( "x=y-5_5y=10+80\r
\n" ); document.write( "\n" ); document.write( "Add 80 to 10 to get 90.
\n" ); document.write( "x=y-5_5y=90\r
\n" ); document.write( "\n" ); document.write( "Divide each term in the equation by 5.
\n" ); document.write( "x=y-5_(5y)/(5)=(90)/(5)\r
\n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common factors.
\n" ); document.write( "x=y-5_y=(90)/(5)\r
\n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by simplifying each term.
\n" ); document.write( "x=y-5_y=18\r
\n" ); document.write( "\n" ); document.write( "Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is 18.
\n" ); document.write( "x=(18)-5_y=18\r
\n" ); document.write( "\n" ); document.write( "Remove the parentheses around the expression 18.
\n" ); document.write( "x=18-5_y=18\r
\n" ); document.write( "\n" ); document.write( "Subtract 5 from 18 to get 13.
\n" ); document.write( "x=13_y=18\r
\n" ); document.write( "\n" ); document.write( "This is the solution to the system of equations.
\n" ); document.write( "x=13_y=18
\n" ); document.write( "
\n" );