document.write( "Question 39135: ay + 3a + 2y + 6 / ay + 3a + 5y + 15 \n" ); document.write( "
Algebra.Com's Answer #24565 by fractalier(6550) You can put this solution on YOUR website! We factor top and bottom \"by grouping,\" so from \n" ); document.write( "ay + 3a + 2y + 6 / ay + 3a + 5y + 15 = \n" ); document.write( "a(y + 3) + 2(y + 3) / a(y + 3) + 5(y + 3) = \n" ); document.write( "(a + 2)(y + 3) / (a + 5)(y + 3) = \n" ); document.write( "(a + 2) / (a + 5) \n" ); document.write( " |