document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38653>Question 38653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pair of vertical angles have degree measure of x2 (x squared) and x + 20. One of the angles can have a measure of ..\r<BR>\n" );
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document.write( "a) 20<BR>\n" );
document.write( "b) 36<BR>\n" );
document.write( "c) 5<BR>\n" );
document.write( "d) 25    THE ANSWER  IS D)25, but why and how to you get this-please explain in detail\r<BR>\n" );
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document.write( "SORRY FOR INCONVENIENCE< BUT YOUR HELP IS MOST APPRECIATED </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24564 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Any time straight lines cross, they make congruent vertical angles.<BR>\n" );
document.write( "Thus x^2 = x + 20<BR>\n" );
document.write( "x^2 - x - 20 = 0<BR>\n" );
document.write( "(x - 5)(x + 4) = 0<BR>\n" );
document.write( "x = 5  (x cannot be negative)<BR>\n" );
document.write( "and if x = 5, the two angles are<BR>\n" );
document.write( "x^2 = 25 and<BR>\n" );
document.write( "x + 20 = 25 </SPAN>\n" );
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