document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343237>Question 343237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an express train leaves grand central station 1 hour after a freight train leaves the same station. the express train is traveling 15 mph faster that the freight treain.find the rate at which each train is traveling if the express train overtakes the freight train in 3 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245594 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> freight train speed be x mph<BR>\n" );
document.write( "express train speed = x+15 mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "the express train leaves the station 1 hour later.\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "express train travels 3(x+15)miles<BR>\n" );
document.write( "freight train travels 4x miles<BR>\n" );
document.write( "4x=3(x+15)<BR>\n" );
document.write( "4x=3x+45<BR>\n" );
document.write( "4x-3x=45<BR>\n" );
document.write( "x=45 mph the speed of freight train.<BR>\n" );
document.write( "speed of express train = x+15 = 60 mph </SPAN>\n" );
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