document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343118>Question 343118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation by using substitution, Bob is one third of the age of his father. In 12 years he will be half the age of his father. How old is each now? Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245571 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Bob is one third of the age of his father\" ___ B = (1/3)f\r<BR>\n" );
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document.write( "\"In 12 years he will be half the age of his father\" ___ B + 12 = (1/2)(f + 12)\r<BR>\n" );
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document.write( "substitute the equivalent value of B from the 1st equation into the 2nd equation and find \"f\"\r<BR>\n" );
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document.write( "then substitute the value of \"f\" into the first equation to find B </SPAN>\n" );
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