document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343079>Question 343079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ages of three brothers are consecutive integers with the sum of 96.  How old are the three brothers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245550 by </B><A HREF=/tutors/aboutme.mpl?userid=katealdridge><B>katealdridge(100)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=katealdridge><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=katealdridge><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Brother  DISABLED_event_one=  x.  Brother two = x+1, since that is the definition of consecutive integers.  Brother three = x+2.  Add them all together and let the sum equal 96.<BR>\n" );
document.write( "x + x+1 + x+2 = 96 combine like terms<BR>\n" );
document.write( "3x + 3 = 96 subtract three from both sides.<BR>\n" );
document.write( "3x = 93 divide both sides by three.<BR>\n" );
document.write( "x = 31.  The youngest brother is 31, therefore, the other brothers are 32 and 33.<BR>\n" );
document.write( "If you have any further questions please check out my facebook page, Kate Calendrillo, tutor.  If you are satisfied with my response, please \"like\" my page. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );