document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=343059>Question 343059</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee wholesaler wants to blend a coffee containing 35% chicory with a coffee containing 15% chicory to produce a 500 kilogram blend of coffee containing 18% chicory. How much of each type is required? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245546 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A coffee wholesaler wants to blend a coffee containing 35% chicory with a coffee containing 15% chicory to produce a 500 kilogram blend of coffee containing 18% chicory. How much of each type is required?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "chicory + chicory = chicory<BR>\n" );
document.write( "0.35x + 0.15(500-x) = 0.18(500)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "35x + 15*500 - 15x = 18*500<BR>\n" );
document.write( "20x = 3*500<BR>\n" );
document.write( "x = 75 kg (amt. of 35% coffee needed in the mixture)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "500-x = 425 kg (amt of 15% coffee needed in the mixture)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );