document.write( "Question 342972: [-4x-5]> -3\r
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document.write( "(The brackets are what i used for the absolute value bars, and the sign is actually greater than or equal to...i just didnt have a way of typing it in the equation) thanks for your help! \n" );
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Algebra.Com's Answer #245469 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! [-4x-5]> -3 \r \n" ); document.write( "\n" ); document.write( "(The brackets are what i used for the absolute value bars, and the sign is actually greater than or equal to...i just didnt have a way of typing it in the equation) thanks for your help!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "okay I think I understand \n" ); document.write( "|-4x - 5| >= -3 --> this is your problem, >= --> used this for greater than or equal to\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "above problem is same as the following problem: \n" ); document.write( "-4x - 5 >= -3 OR -4x - 5 <= 3 \n" ); document.write( "-4x >= 2 OR -4x <= 8 (same operation both sides of >= sign) \n" ); document.write( "x <= 2/(-4) OR x >= 8/(-4) (flipped sign since divided by negative) \n" ); document.write( "x <= -1/2 OR x >= -2 \n" ); document.write( "answer set: (-infinity,-1/2]U[-2,+infinity} (the bracket means inclusion in the set, the \"U\" means union), the 2 sets in the union overlap, seems all values of x are solutions\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |