document.write( "Question 342971: Half the supplement of an angle is 12 degrees less than twice the complement of the angle. Find the measure of the larger angle. \n" ); document.write( "
Algebra.Com's Answer #245453 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "1.\"A%2BC=90\"
\n" ); document.write( "2.\"A%2BS=180\"
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\n" ); document.write( "\"%281%2F2%29S=2C-12\"
\n" ); document.write( "Multiply both sides by 2.
\n" ); document.write( "3.\"S=4C-48\"
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\n" ); document.write( "Subtract eq. 1 from eq. 2,
\n" ); document.write( "\"A%2BS-A-C=180-90\"
\n" ); document.write( "\"S-C=90\"
\n" ); document.write( "Substitute eq. 3,
\n" ); document.write( "\"%284C-48%29-C=90\"
\n" ); document.write( "\"3C-48=90\"
\n" ); document.write( "\"3C=138\"
\n" ); document.write( "\"C=46\" degrees
\n" ); document.write( "Then,
\n" ); document.write( "\"S-46=90\"
\n" ); document.write( "\"highlight%28S=136%29\" degrees
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