document.write( "Question 342932: I have some factoring problems.. I have solved some, but the others just dont work.\r
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document.write( "3x(a-3)-5(3-a) I don't even know where to start, it looks factored to me?\r
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document.write( "20x^2-7x-6. I have tried about every different combination I can for foil for this one, it just does not work itself out.. It is driving me CRAZY!!!\r
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document.write( "4x^4 + 12x^3- 28x^2. I don't even know where to start to be honest. Is this a foil problem?\r
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document.write( "Thank you for your time..I can not tell you how valuable this site has been to me. \n" );
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Algebra.Com's Answer #245430 by akc(7)![]() ![]() You can put this solution on YOUR website! Please post one question is a post.\r \n" ); document.write( "\n" ); document.write( "1. \n" ); document.write( "3x(a-3)-5(3-a) (factorisaton means there should not be + or - between two terms) \n" ); document.write( "=3x(a-3)-5(-(a-3)) [-(a-3)= 3-a] \n" ); document.write( "=3x (a-3)+ 5 (a-3) [two - equals +] \n" ); document.write( "=(a-3)(3x + 5) [taking (a-3) common from both terms] \n" ); document.write( "(a-3) & (3x+5) are the factors. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "2. \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= (4x-3)(5x + 2) \n" ); document.write( "(4x-3)&(5x + 2) are the factors \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "3. \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Again plz ask single question at a time. you can email me for immediate help. my email is akc1@uno.edu \n" ); document.write( " |