document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=342925>Question 342925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary angles.  The measure of the larger angle is 5 degrees more than 3 times the measure of the smaller angle.  find the measure of the two angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245425 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = bigger angle\r<BR>\n" );
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document.write( "Let y = smaller angle\r<BR>\n" );
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document.write( "x + y = 180\r<BR>\n" );
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document.write( "x = 3y + 5\r<BR>\n" );
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document.write( "I will solve by substitution.\r<BR>\n" );
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document.write( "3y + 5 + y = 180\r<BR>\n" );
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document.write( "4y + 5 = 180\r<BR>\n" );
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document.write( "4y = 180 - 5\r<BR>\n" );
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document.write( "4y = 175\r<BR>\n" );
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document.write( "y = 175/4\r<BR>\n" );
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document.write( "y = 43.75 degrees.\r<BR>\n" );
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document.write( "The smaller angle is 43.75 degrees.\r<BR>\n" );
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document.write( "The larger angle is 180 - 43.75 or 136.25 degrees.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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